我有两个长，但sorting的文件。 如何获取不在第二个文件中的第一个文件的所有行？
文件1
0000_aaa_b 0001_bccc_b 0002_bcc <------ file2 have not that line 0003_aaa_d 0006_xxx ... 文件2
0000_aaa_b 0001_bccc_b 0003_aaa_d 0006_xxx ...
这是comm命令的用途：
$ comm -3 file1 file2 0002_bcc
从man comm ：
DESCRIPTION Compare sorted files FILE1 and FILE2 line by line. With no options, produce three-column output. Column one contains lines unique to FILE1, column two contains lines unique to FILE2, and column three contains lines common to both files. -1 suppress column 1 (lines unique to FILE1) -2 suppress column 2 (lines unique to FILE2) -3 suppress column 3 (lines that appear in both files)
只要在他们身上运行diff ：
diff -c file1 file2
-c （对于“上下文”）标志将只显示不同的行，每行包围两行。