如何打印特定格式的time_t?

ls命令以这种格式打印间:

Aug 23 06:07 

如何将从stat()mtime()收到的时间转换为当地时间的格式?

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使用strftime (您需要将time_t转换为struct tm* ):

 char buff[20]; struct tm * timeinfo; timeinfo = localtime (&mtime); strftime(buff, sizeof(buff), "%b %d %H:%M", timeinfo); 

格式:

 %b - The abbreviated month name according to the current locale. %d - The day of the month as a decimal number (range 01 to 31). %H - The hour as a decimal number using a 24-hour clock (range 00 to 23). %M - The minute as a decimal number (range 00 to 59). 

以下是完整的代码:

 struct stat info; char buff[20]; struct tm * timeinfo; stat(workingFile, &info); timeinfo = localtime (&(info.st_mtime)); strftime(buff, 20, "%b %d %H:%M", timeinfo); printf("%s",buff);