fatal: not enough arguments to satisfy format string `%s SPT=80' ^ ran out for this one 这是我的代码
for ((h = 1 ; h < 4 ; h++ )); do x=$(awk -vi=h -vj=17 'FNR == 2 {printf "%s " $j}' newiptables.log) echo $x
这是我的文件
Dec 26 09:17:51 localhost kernel: IN=eth0 OUT= MAC=00:10:c6:a8:da:68:00:90:7f:9c:50:5a:08:00 SRC=198.252.206.16 DST=10.128.1.225 LEN=313 TOS=0x00 PREC=0x00 TTL=64 ID=59334 PROTO=TCP SPT=80 DPT=56506 WINDOW=46535 RES=0x00 ACK PSH URGP=0 Dec 26 09:17:52 localhost kernel: IN=eth0 OUT= MAC=00:10:c6:a8:da:68:00:90:7f:9c:50:5a:08:00 SRC=198.252.206.16 DST=10.128.1.225 LEN=1440 TOS=0x00 PREC=0x00 TTL=64 ID=47303 PROTO=TCP SPT=80 DPT=56506 WINDOW=46535 RES=0x00 ACK URGP=0 Dec 26 09:17:52 localhost kernel: IN=eth0 OUT= MAC=00:10:c6:a8:da:68:00:90:7f:9c:50:5a:08:00 SRC=198.252.206.16 DST=10.128.1.225 LEN=1440 TOS=0x00 PREC=0x00 TTL=64 ID=47559 PROTO=TCP SPT=80 DPT=56506 WINDOW=46535 RES=0x00 ACK URGP=0
问题是在awk的printf命令中缺少一个逗号：
awk -vi=h -vj=17 'FNR == 2 {printf "%s ", $j}' newiptables.log ^ |== This is needed
从手册引用：
一个简单的
printf语句如下所示：printf format, item1, item2, ...