boost :: bind返回一个函数对象，它是需要指针的函数的参数

我正在Linux上做关于boost :: bind的C ++编码。

boost :: bind的返回数据types是一个函数对象，它是另一个函数bridge_set_pound_var_func的input参数。

但是，bridge_set_pound_var_func的input参数必须是一个函数指针。 bridge_set_pound_var_func的接口无法更改。

代码如下：

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#include <boost/bind.hpp> #include <iostream> using namespace boost; class myA { public: int bridge_set_pound_var_func( int (*pound_var_func)(const char *, char *, void *), void *arg ) { std::cout << "bridge_set_pound_func is called " << std::endl ; return 0; } }; class myC { public: myA *myOA; int func(const char * poundVar , char * t1, void * t2); int myCCall() { myOA->bridge_set_pound_func( (boost::bind(&myC::func, this)), (void *)this ); return 0;} }; int myC::func(const char * poundVar , char * t1, void * t2) { std::cout << "myC::func is called " << std::endl; return 1; } int main() { myC myCO ; myC *m1p = &myCO ; m1p->myCCall() ; return 0 ; } // EOF 

我有编译错误：

  error: no matching function for call to 'myA::bridge_set_pound_func(boost::_bi::bind_t<int (&)(const char*, char*, void*), boost::_mfi::dm<int ()(const char*, char*, void*), myC>, boost::_bi::list1<boost::_bi::value<myC*> > >, void*)' note: candidates are: int myA::bridge_set_pound_func(int (*)(const char*, char*, void*), void*) 

任何帮助将不胜感激。

而且，bridge_set_pound_var_func的接口不能被更改，因为它需要被许多其他函数调用。

这是工作的新代码。 但是，“myC :: func被调用”不打印，为什么？

 #include <boost/bind.hpp> #include <boost/function.hpp> #include <iostream> using namespace boost; class myA { public: int bridge_set_pound_var_func( const boost::function3<int, const char *, char *, void *> f, void *arg ) { std::cout << "bridge_set_pound_var_func is called " << std::endl ; return 0; } }; typedef int (*funcPtr)(const char *, char *, void *) ; typedef boost::function0<int&> boostBindFuncType; class myC { public: myA *myOA; int func(const char * poundVar , char * t1, void * t2); int myCCall() { std::cout << "myCCall is called " << std::endl; myOA->bridge_set_pound_var_func( (boost::bind(&myC::func, this, _1, _2, _3)), (void *)this ); return 0; } }; int myC::func(const char * poundVar , char * t1, void * t2) { std::cout << "myC::func is called " << std::endl; return 1; } int main() { myC myCO ; myC *m1p = &myCO ; m1p->myCCall() ; return 0 ; } 

我不能改变被许多其他函数调用的bridge_set_pound_var_func的接口。 是否有可能将boost :: bind返回的函数对象转换为函数指针？

 class myC { public: myA *myOA; //NOTE: I've removed the void* ptr here, which should be user data. // If you still need it you'll need to bind it away at functor creation time. int func(const char * poundVar , char * t1); int myCCall() { //TODO: Fix this intentional leak. boost::function<int(const char*, char*)> * fn = new boost::function<int(const char*,char*)>( boost::bind(&myC::func,this) ); //Call our helper function instead of `set_pound_func`. set_pound_func_with_functor(myOA, fn ); return; } }; // Function that is really passed to `set_pound_func` when // set_pound_func_with_functor is called. // It converts the user data back to a boost function and calls it. int pound_func_with_functor(const char* d1, char* d2, void* user_data) { boost::function<int(const char*,char*)> * fn = static_cast< boost::function<int(const char*, char*) >( user_data ); return (*fn)(d1,d2); } //Helper function to make set_pound_func work with boost functions instead. //NOTE: You are required to ensure the fn argument exists for long enough... void set_pound_func_with_functor( myA * myOA, boost::function<int(const char *, char *)> & fn ) { myOA->bridge_set_pound_var_func( &pound_func_with_functor, &fn ); } 

 int bridge_set_pound_var_func ( const boost::function<int(const char *, char *, void *)>& f, void *arg ) 

 myOA->bridge_set_pound_var_func( (boost::bind(&myC::func, this, _1, _2, _3)), (void *)this ); 

 template<typename Func> int bridge_set_pound_var_func( const Func& f, void *arg )