我试图在包含类似'ls -l'输出的文件中使用fullpath grep一个文件名，但它无法正确匹配它。
在执行stringsearch的shell脚本中行
pcline=`grep -w "$file1" $file2` # grep for file1 in file2 contents 如果我回应命令，命令的输出如下所示
grep -w run /home/rajesh/rootfs.layout Expected lrwxrwxrwx 1 root root 3 Aug 28 run Actual lrwxrwxrwx 1 root root 7 Aug 28 bin/run-parts lrwxrwxrwx 1 root root 3 Aug 28 run -rwxr-xr-x 1 root root 303 Aug 28 tests/aes/run.sh -rwxr-xr-x 1 root root 445 Aug 28 tests/auto_ui/run.sh -rwxr-xr-x 1 root root 320 Aug 28 tests/available_memory/run.sh -rwxr-xr-x 1 root root 308 Aug 28 tests/fonts/run.sh -rwxr-xr-x 1 root root 309 Aug 28 tests/html_config_page/run.sh -rwxr-xr-x 1 root root 361 Aug 28 tests/ipc/run.sh -rwxr-xr-x 1 root root 304 Aug 28 tests/JSON/run.sh -rwxr-xr-x 1 root root 303 Aug 28 tests/log4cplus_cpp/run.sh -rwxr-xr-x 1 root root 301 Aug 28 tests/log4cplus_c/run.sh -rwxr-xr-x 1 root root 751 Aug 28 tests/msm_basic/run.sh -rwxr-xr-x 1 root root 472 Aug 28 tests/res_man_dependency/run.sh -rwxr-xr-x 1 root root 465 Aug 28 tests/res_man_ipc/run.sh -rwxr-xr-x 1 root root 789 Aug 28 tests/res_man_multi_process/run.sh -rwxr-xr-x 1 root root 469 Aug 28 tests/res_man_private_client/run.sh -rwxr-xr-x 1 root root 492 Aug 28 tests/res_man_public_client/run.sh -rwxr-xr-x 1 root root 311 Aug 28 tests/virt_mem_config/run.sh lrwxrwxrwx 1 root root 6 Aug 28 var/run]
我试过的技巧是添加一个白色的空间，这是保证在我的input文件，这在控制台工作，但不是当它被分配给一个variables。
grep " tests/aes/run.sh" /home/rajesh/rootfs.layout
在脚本中行
pcline=`grep \"" $file1"\" $file2` # grep for file1 in file2 contents
请让我知道，如果我已经犯了这个脚本中的任何错误。
你可以像这样使用egrep ：
egrep "(^| )$file1( |$)" "$file2"
如果file1="run"那么上面的命令将匹配以行开头或空格开头的字符串，然后是空格或行结束。