ls命令以这种格式打印时间：
Aug 23 06:07 如何将从stat()的mtime()收到的时间转换为当地时间的格式？
使用strftime （您需要将time_t转换为struct tm* ）：
char buff[20]; struct tm * timeinfo; timeinfo = localtime (&mtime); strftime(buff, sizeof(buff), "%b %d %H:%M", timeinfo);
格式：
%b - The abbreviated month name according to the current locale. %d - The day of the month as a decimal number (range 01 to 31). %H - The hour as a decimal number using a 24-hour clock (range 00 to 23). %M - The minute as a decimal number (range 00 to 59).
以下是完整的代码：
struct stat info; char buff[20]; struct tm * timeinfo; stat(workingFile, &info); timeinfo = localtime (&(info.st_mtime)); strftime(buff, 20, "%b %d %H:%M", timeinfo); printf("%s",buff);