我怎样才能模拟在x,y坐标,使用SendInput的双击鼠标(我khow句柄)上的双击鼠标?

我怎样才能模拟双击鼠标点击窗口(我知道这个窗口的句柄)在x,y坐标,使用SendInput?

void DoubleClick(int x, int y) { const double XSCALEFACTOR = 65535 / (GetSystemMetrics(SM_CXSCREEN) - 1); const double YSCALEFACTOR = 65535 / (GetSystemMetrics(SM_CYSCREEN) - 1); POINT cursorPos; GetCursorPos(&cursorPos); double cx = cursorPos.x * XSCALEFACTOR; double cy = cursorPos.y * YSCALEFACTOR; double nx = x * XSCALEFACTOR; double ny = y * YSCALEFACTOR; INPUT Input={0}; Input.type = INPUT_MOUSE; Input.mi.dx = (LONG)nx; Input.mi.dy = (LONG)ny; Input.mi.dwFlags = MOUSEEVENTF_MOVE | MOUSEEVENTF_ABSOLUTE | MOUSEEVENTF_LEFTDOWN | MOUSEEVENTF_LEFTUP; SendInput(1,&Input,sizeof(INPUT)); SendInput(1,&Input,sizeof(INPUT)); Input.mi.dx = (LONG)cx; Input.mi.dy = (LONG)cy; Input.mi.dwFlags = MOUSEEVENTF_MOVE | MOUSEEVENTF_ABSOLUTE; SendInput(1,&Input,sizeof(INPUT)); } 

您可以使用GetWindowRect()从其句柄获取窗口位置,并将相对xy传递给DoubleClick函数:

 RECT rect; GetWindowRect(hwnd, &rect); HWND phwnd = GetForegroundWindow(); SetForegroundWindow(hwnd); DoubleClick(rect.left + x, rect.top + y); SetForegroundWindow(phwnd); // To activate previous window 

这将模拟在某些坐标处的双击

  SetCursorPos(X,Y); mouse_event(MOUSEEVENTF_LEFTDOWN | MOUSEEVENTF_LEFTUP,0,0,0,0); mouse_event(MOUSEEVENTF_LEFTDOWN | MOUSEEVENTF_LEFTUP,0,0,0,0); 

你可以指定你的目标(最好)或者方法,但是如果你试图指定这两个目标,那么答案往往是“那不行”。

SendInput不能这样工作,它会模拟鼠标在屏幕上的活动,它将被传递到该位置可见的任何窗口(或者有鼠标捕捉),而不是您选择的窗口。

要传递双击到特定窗口,请尝试PostMessage(hwnd, WM_LBUTTONDBLCLK, 0, MAKEDWORD(x, y))

这个网站有一段代码 尝试连续两次使用函数LeftClick() 根据这家伙做的伎俩。

由于我的'声望'还不够高,我想对#fardjad的解决方案发表评论:它的效果很好,但是可以在“main”例程中添加以下内容:

 SetForegroundWindow(hwnd); SetCursorPos(rect.left + x, rect.top + y); // which shows your current mouseposition... // during my testing, I used a _getch() so that I actually could verify it Sleep(nWinSleep); // delay the mouseclick, as window might not get to foreground quick enough; took me awhile to figure this one out... DoubleClick(rect.left + x, rect.top + y);