程序获取“expression式：string下标超出范围”

#include <iostream> #include <string> using namespace std; string Latin(string words) { string strWord, strSentence = ""; int length = 0, index = 0; while (words[index] != '\0') { if(words.find(' ', index) != -1) { length = words.find(' ', index); length -= index; strWord = words.substr(index,length); strWord.insert(length, "ay"); strWord.insert(length, 1, words[index]); strWord.erase(0,1); index += length +1; } else { strWord = words.substr(index); length = strWord.length(); strWord.insert(length, "ay"); strWord.insert(length,1,words[index]); strWord.erase(0,1); index = words.length(); } strSentence += (strWord + " "); } return strSentence; } int main() { string str; getline(cin,str); str = Latin(str); cout<<str<<endl; return 0; } 

我得到这个错误说

我不知道该怎么做。 正如我刚刚所说，这是一个程序，它是要求用户input一段文字，并将它们翻译成猪拉丁文。 任何帮助将不胜感激。

 std::string line; std::getline(std::cin, line); std::stringstream buffer(line); std::stringstream result; std::transform(std::istream_iterator<std::string>(buffer), std::istream_iterator<std::string>(), std::ostream_iterator<std::string>(result, " "), [](std::string s) { std::rotate(s.begin(), s.begin() + 1, s.end()); s += "ay"; return s; });