如何在Linux中按数字sorting文件？

我的程序读入从文件名parsing的数字。我想要它的顺序是如何，但在这个例子中，列表为500,4000,7000。我的命名约定应该如何实现呢？也就是说，当我递增数字的时候，它从小到大列出来。

我真正想要的是它按排名（这里从零开始）进行sorting，然后按递增的数字对它进行sorting.. 500，5000，7000。

在这里输入图像描述

期望的输出

LOG-rank-0-die-10-delay-500.txt LOG-rank-0-die-10-delay-4000.txt LOG-rank-0-die-10-delay-7000.txt LOG-rank-1-die-10-delay-500.txt LOG-rank-1-die-10-delay-4000.txt LOG-rank-1-die-10-delay-7000.txt LOG-rank-2-die-10-delay-500.txt LOG-rank-2-die-10-delay-4000.txt LOG-rank-2-die-10-delay-7000.txt

相关守则

 for filenamelogs in sorted(os.listdir(log_directory)): for each_line in filenamelogs: #various file parsing activity

我将数据逐个文件附加到各种arrays。不幸的是，如果我不能按请求的顺序对文件进行sorting，这对我来说是非常糟糕的。也许我的问题是转向开发一个自定义的方法来读取我提供的sorting约束下的文件。

从博客链接的博客评论：

 >>> import re >>> def sort_nicely(l): ... """ ... Sort the given list in the way that humans expect. Modifies the original list. ... """ ... convert = lambda text: int(text) if text.isdigit() else text ... alphanum_key = lambda key: [convert(c) for c in re.split('([0-9]+)', key)] ... l.sort(key=alphanum_key) ... >>> mylist = ['LOG-rank-0-die-10-delay-500.txt', ... 'LOG-rank-0-die-10-delay-4000.txt', ... 'LOG-rank-0-die-10-delay-7000.txt', ... 'LOG-rank-1-die-10-delay-500.txt', ... 'LOG-rank-1-die-10-delay-4000.txt', ... 'LOG-rank-1-die-10-delay-7000.txt', ... 'LOG-rank-2-die-10-delay-500.txt', ... 'LOG-rank-2-die-10-delay-4000.txt', ... 'LOG-rank-2-die-10-delay-7000.txt'] >>> sort_nicely(mylist) >>> print(*mylist, sep='\n') LOG-rank-0-die-10-delay-500.txt LOG-rank-0-die-10-delay-4000.txt LOG-rank-0-die-10-delay-7000.txt LOG-rank-1-die-10-delay-500.txt LOG-rank-1-die-10-delay-4000.txt LOG-rank-1-die-10-delay-7000.txt LOG-rank-2-die-10-delay-500.txt LOG-rank-2-die-10-delay-4000.txt LOG-rank-2-die-10-delay-7000.txt

要return一个新的排序list而不是修改原来的list ：

 >>> def sort_nicely(l): ... """ ... Sort the given list in the way that humans expect. Returns a new list. ... """ ... convert = lambda text: int(text) if text.isdigit() else text ... alphanum_key = lambda key: [convert(c) for c in re.split('([0-9]+)', key)] ... return sorted(l, key=alphanum_key) ... >>> newlist = sort_nicely(mylist) >>> print(*newlist, sep='\n')