我正在开发一个Java程序运行在树莓派，我不能让它运行使用terminal。
它由两个类组成，这两个类都位于：
/home/pi/JBerries/Access control/bin/access/control 另外请注意，这是一个使用swing制作的GUI程序。
这是我用来尝试运行它的命令：
pi@raspberrypi ~/JBerries/Access control $ java -classpath .bin.access.control.accessControlUI
这就是它吐出来的东西：
Usage: java [-options] class [args...] (to execute a class) or java [-options] -jar jarfile [args...] (to execute a jar file) where options include: -d32 use a 32-bit data model if available -d64 use a 64-bit data model if available -client to select the "client" VM -server to select the "server" VM The default VM is client. -cp <class search path of directories and zip/jar files> -classpath <class search path of directories and zip/jar files> A : separated list of directories, JAR archives, and ZIP archives to search for class files. -D<name>=<value> set a system property -verbose:[class|gc|jni] enable verbose output -version print product version and exit -version:<value> require the specified version to run -showversion print product version and continue -jre-restrict-search | -no-jre-restrict-search include/exclude user private JREs in the version search -? -help print this help message -X print help on non-standard options -ea[:<packagename>...|:<classname>] -enableassertions[:<packagename>...|:<classname>] enable assertions with specified granularity -da[:<packagename>...|:<classname>] -disableassertions[:<packagename>...|:<classname>] disable assertions with specified granularity -esa | -enablesystemassertions enable system assertions -dsa | -disablesystemassertions disable system assertions -agentlib:<libname>[=<options>] load native agent library <libname>, eg -agentlib:hprof see also, -agentlib:jdwp=help and -agentlib:hprof=help -agentpath:<pathname>[=<options>] load native agent library by full pathname -javaagent:<jarpath>[=<options>] load Java programming language agent, see java.lang.instrument -splash:<imagepath> show splash screen with specified image See http://www.oracle.com/technetwork/java/javase/documentation/index.html for more details.
这是一个迹象表明我的程序已经准备就绪，我只需要包含某种启动选项？ 任何帮助将非常感激。
尝试
java -classpath . bin.access.control.accessControlUI
注意之间的“空间”。 和斌